# Line slope calculator x+5y=21

**Straight line given by points A[1; 4] and B[6; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.2x+4.2

**Canonical form of the line equation:**x+5y-21 = 0

**Parametric form of the line equation:**

x = 5t+1

y = -t+4 ; t ∈ R

**Slope:**m = -0.2

**Slope angle of line: φ =**-11°18'36″ = -0.1974 rad

**X intercept:**x

_{0}= 21

**Y intercept:**y

_{0}= q = 4.2

**Distance line from the origin:**d

_{0}= 4.1184

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; -1)

**Normal vector: n =**(1; 5)

**Midpoint of the segment AB: M =**[3.5; 3.5]

**Perpendicular Bisector equation:**5x-y-14 = 0

**Vector OA = (1; 4) ; |OA| = 4.1231**

**Vector OB = (6; 3) ; |OB| = 6.7082**

**Scalar product OA .OB = 18**

**Angle ∠ AOB = 49°23'55″ = 0.8622 rad**